This is how it would break down, say B is the dominant gene for black nose, and say p is recessive gene for pink noses. You would need both recessive genes from the parents to have a pink nose
Both parents carry recessive gene
Bp X Bp = BB- black nose
Bp- black nose
Bp- black nose
pp- pink nose
One parent carries recessive gene
BB X Bp = BB- Black
BB- Black BB does not carry gene for pink nose, you cannot breed anything to him and get a pink nose
Bp- Black
Bp- Black Bp is a carrier for recessive gene
pp X Bp = Bp
Bp 1/2 black
pp
pp 1/2 pink
BB X pp = Bp
Bp
Bp
Bp Whole litter would have black noses, but would all be carriers of gene
Perfect form, thank you sir. Im on myphone driving and couldn't have handled that with the finesse you did.
